Universal - Maths tutor - Bikaner
1st lesson free
Universal - Maths tutor - Bikaner

Universal

  • Rate 173 GHS
  • Response 1h
Universal - Maths tutor - Bikaner

173 GHS/hr

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths

Yesi am pankaj kumarIam study my math best my favourite subject math

  • Maths

Lesson location

About Universal

We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: 𝑃(π‘˜ heads in 𝑛 tosses)=(π‘›π‘˜)β‹…π‘π‘˜β‹…π‘žπ‘›βˆ’π‘˜ Plugging in the values: 𝑃(2 heads in 3 tosses)=(32)β‹…(0.5)2β‹…(0.5)1=3β‹…0.25β‹…0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.

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About the lesson

  • Primary school
  • Junior high school
  • SHS 1
  • +14
  • levels :

    Primary school

    Junior high school

    SHS 1

    SHS 2

    SHS 3

    BTS

    University education

    Adult Education

    Facultate (LicenΘ›Δƒ)

    Master's degree

    Higher national diploma

    Doctor of philosophy

    Other

    GDL

    Qualified Lawyer Transfer Scheme

    MBA

    Pre school

  • English

All languages in which the lesson is available :

English

The probability of getting exactly \(2\) heads in \(3\) coin tosses is \(0.375\). We are asked to find the probability of getting exactly 2 heads in 3 coin tosses. Assuming the coin is fair, the probability of heads (p) = 0.5 and the probability of tails (q) = 0.5. Each toss is independent. This is a binomial probability problem, where: n = number of trials = 3 k = number of desired successes (heads) = 2 p = probability of success = 0.5 q = probability of failure = 0.5 The binomial probability formula is: 𝑃(π‘˜ heads in 𝑛 tosses)=(π‘›π‘˜)β‹…π‘π‘˜β‹…π‘žπ‘›βˆ’π‘˜ Plugging in the values: 𝑃(2 heads in 3 tosses)=(32)β‹…(0.5)2β‹…(0.5)1=3β‹…0.25β‹…0.5=0.375 Final Answer: The probability of getting exactly 2 heads in 3 coin tosses is 0.375 or 37.5%.

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Rates

Rate

  • 173 GHS

Pack prices

  • 5h: 865 GHS
  • 10h: 1730 GHS

free lessons

The first free lesson with Universal will allow you to get to know each other and clearly specify your needs for your next lessons.

  • 1hr

online

  • GHS173/h

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