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Tanushree
- Rate 123 GHS
- Response 1h

123 GHS/hr
1st lesson free
- Maths
- Algebra
- Trigonometry
- Arithmetic
Hello, I am Tanushree Das. I am 12th pass. I had taken PCMB in class 11. I got 90.8% in 12th boards and 94% in 10th boards.
- Maths
- Algebra
- Trigonometry
- Arithmetic
Lesson location
About Tanushree
Hello students, I am here to teach you math. I have scored 98 in 12th boards and 99 in 10th boards. Believe me, math is not that hard. Math is all about practicing and using a little knowledge. I'm here to give you that knowledge, through which you can gain the confidence to solve new problems in a few minutes.
About the lesson
- Primary school
- Junior high school
- SHS 1
- +14
levels :
Primary school
Junior high school
SHS 1
SHS 2
SHS 3
BTS
University education
Adult Education
Facultate (Licență)
Master's degree
Higher national diploma
Doctor of philosophy
Other
GDL
Qualified Lawyer Transfer Scheme
MBA
Pre school
- English
All languages in which the lesson is available :
English
I will teach you easy tricks of math. Math will be no more a boring subject for you all. Just like if, 🟦 Trigonometry Problem: Height of a Building Problem: A person is standing 30 meters away from the base of a building. The angle of elevation from the person’s eyes to the top of the building is 45°. Find the height of the building. (Assume the person’s eye level is at ground level for simplicity.) --- Solution: Use of Tangent Function From the right-angled triangle formed: Let the height of the building = h Distance from the building = 30 meters Angle of elevation = 45° \tan(45°) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{30} But we know: \tan(45°) = 1 So, 1 = \frac{h}{30} \Rightarrow h = 30 --- Final Answer: The building is 30 meters
Rates
Rate
- 123 GHS
Pack prices
- 5h: 615 GHS
- 10h: 1230 GHS
online
- GHS123/h
free lessons
The first free lesson with Tanushree will allow you to get to know each other and clearly specify your needs for your next lessons.
- 1hr
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