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Jyotirmay
- Rate 238 GHS
- Response 1h
238 GHS/hr
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- Maths
- Trigonometry
- Arithmetic
- Geometry
- Logic
Computer science engineer with about 5years industry experience, currently pursuing masters in Information systems from UCD. I have experience in home tutoring in subjects like maths, computer, englis
- Maths
- Trigonometry
- Arithmetic
- Geometry
- Logic
Lesson location
About Jyotirmay
Computer science engineer by profession with approximately 5years of industry experience, currently pursuing Masters in Information Systems from University College Dublin. I have experience in home tutoring for student from the age of 6-15yrs in multiple subjects like maths, computers, social sciences, english.
I am a friendly person who believes learning is a process where we unlearn and learn things. In this tutoring process not only will you as student gain knowledge from me but I will too learn multiple things from you. I believe in happy friendly learning process.
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About the lesson
- Primary school
- Junior high school
- SHS 1
- +9
levels :
Primary school
Junior high school
SHS 1
SHS 2
SHS 3
Adult Education
Facultate (Licență)
Master's degree
Higher national diploma
Doctor of philosophy
Other
WASCE
- English
All languages in which the lesson is available :
English
Computer science engineer by profession with approximately 5years of industry experience, currently pursuing Masters in Information Systems from University College Dublin. I have experience in home tutoring for student from the age of 6-15yrs in multiple subjects like maths, computers, social sciences, english.
I prefer 1hour teaching rule, as I believe any individual's mind works most efficiently during the first hour of the learning process. During the 1hour I would teach the student the concept and make them well verse the topic with help of examples.
For example: learning the formula for total area of a cylinder. One can either memorize the formula or understand the underlying concept and remember the formula forever.
Cylinder consists of two circles one at top and other at bottom.
Therefore area of two circles 2pir^2
If we remove the top and bottom and cut the cylinder vertically straight, we will have a rectangle with length as height of cylinder and breadth as circumference of the circle. Area = 2pirh
Therefore total surface area = 2pir^2 + 2pirh = 2pir(r+h)
Learning can be made simple and effective if we go by logic and real time examples.
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Rates
Rate
- 238 GHS
Pack prices
- 5h: 1190 GHS
- 10h: 2380 GHS
online
- GHS238/h
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